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[Figure: a block of mass m on a frictionless horizontal surface, joined to a left-hand wall by a spring of constant K₁ and to a right-hand wall by a spring of constant K₂.] A mass m is attached to two springs of constants K₁ and K₂ as shown. The surface is frictionless. The time period of oscillation of the mass is

Asked in JEE Main 6th April 1st Shift 2023 · Spring combinations

• (1) 1/(2π)√(K₁-K₂)/m
• (2) 1/(2π)√(K₁+K₂)/m
• (3) 2π√m/(K₁-K₂)
• (4) 2π√m/(K₁+K₂)

Step-by-step solution

Why the other options are wrong

• (1) This is a frequency, and it subtracts the two constants.
• (2) This is the frequency, not the period.
• (3) Subtracts the constants, as though the two springs opposed each other.

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