Practice portal › Oscillations › Oscillations due to a Spring

[Figure: a block on a frictionless horizontal surface attached by a spring to a rigid wall.] For a mass-spring system on a frictionless surface, the angular frequency is ω₁ when the block has mass 1 kg and ω₂ when it has mass 2 kg. The ratio (ω₂)/(ω₁) is

Asked in JEE Main 30th Jan 2nd Shift 2023 · Single spring

Figure: Single spring
Answer: (4) 1/(√2)

Step-by-step solution

ω=√k/m with the same spring, so ω∝1/(√m).

(ω₂)/(ω₁)=√1/2=1/(√2).

Why the other options are wrong

More Oscillations due to a Spring questionsAll Oscillations due to a Spring questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer