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Two massless springs of constants 2k and 9k carry masses of 50 g and 100 g at their free ends. The two masses oscillate vertically with equal maximum velocities. The ratio of their amplitudes is

Asked in JEE Main 24th June 2nd Shift 2022 · Single spring

Answer: (2) 3:2

Step-by-step solution

Equal vₘₐₓ=Aω gives A∝1/ω=√m/k.

(A₁)/(A₂)=√(0.05)/(2k)×(9k)/(0.10)=√(0.45)/(0.20)=√2.25=1.5, i.e. 3:2.

Why the other options are wrong

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