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Two bodies A and B of equal mass hang from two massless springs of spring constants k₁ and k₂ respectively. They oscillate vertically with equal amplitudes. The ratio of the maximum velocity of A to that of B is

Asked in JEE Main 29th Jan 2nd Shift 2025 · Single spring

Answer: (3) √(k₁)/(k₂)

Step-by-step solution

vₘₐₓ=Aω and the amplitudes are equal, so (v_A)/(v_B)=(ω₁)/(ω₂).

With equal masses ω=√k/m, so the ratio is √(k₁)/(k₂).

Why the other options are wrong

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