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A ray of light travelling in impure water is incident on a glass plate immersed in it. When the angle of incidence is 51° the reflected ray is totally plane polarised. The refractive index of the impure water is 1.4. The refractive index of the glass should be (tan 51°=1.235)

Asked in GUJCET 2018 · Brewster's law and polarisation by reflection

Answer: (4) 1.73

Step-by-step solution

Given: μ_w=1.4, polarising angle 51°, tan 51°=1.235.

Idea: when the reflected ray is completely polarised, Brewster's law holds with the index of the glass measured relative to the medium the light is travelling in, tan iₚ=(μ_g)/(μ_w).

μ_g=μ_w tan iₚ=1.4×1.235.

μ_g=1.729.

μ_g≈1.73.

Why the other options are wrong

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