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A plane polarized light is incident normally on a tourmaline plate. Its ⃗E vectors make an angle of 60° with the optic axis of the plate. Find the percentage difference between initial and final intensities.

Asked in GUJCET 2015 · Malus's law and polaroids

Answer: (3) 75%

Step-by-step solution

Given: plane-polarised light falls normally on a tourmaline plate with its ⃗E at 60° to the plate's optic axis.

Idea: Malus's law. Only the component of ⃗E along the transmission axis gets through, so the amplitude is cut to E₀ cos θ and the intensity to I = I₀ cos²θ.

I = I₀ cos²60° = I₀(1/2)² = (I₀)/4.

Intensity lost: I₀ - (I₀)/4 = (3I₀)/4.

As a fraction of what went in, that is 3/4 = 75%.

So the intensity drops by 75%.

Why the other options are wrong

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