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Asked in RS Academy GUJCET booklet · Snell's law, slabs and apparent depth
Given: 30 cm of water (n=1.33) with 30 cm of oil (n=1.28) floating on it, viewed from above.
Idea: each layer of thickness t raises everything below it by t(1-1/n), and since the shifts are all measured along the same vertical line they simply add.
Water: 30(1-1/(1.33))=30× 0.248=7.44 cm
Oil: 30(1-1/(1.28))=30× 0.219=6.56 cm
Total shift =7.44+6.56=14 cm
The oil contributes a little less than the water because it is optically the thinner of the two.
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