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Asked in GSEB Board March 2022 · Relation between field and potential
Given: ⃗E = 20 N C⁻¹ ̂i; A at (0, 3) mm and B at (0, 4) mm.
Idea: V_B - V_A = -⃗E·Δ⃗r.
The displacement from A to B is Δ⃗r = (1 mm) ̂j, which is perpendicular to ̂i.
So ⃗E·Δ⃗r = 0 and V_B - V_A = 0.
Both points lie on the equipotential plane x = 0 (in a uniform field the equipotentials are planes perpendicular to ⃗E).
So V_A = V_B.
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