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Asked in GUJCET 2025 · Potential of point charges
Given: a square of side 2l with +q at the two ends of the left side and -q at the other two corners; A is the mid-point of the side joining the +q charges, so the figure marks l from the top-left corner down to A and 2l for the full side.
Idea: add the four potentials as signed scalars, V=Σ(kqᵢ)/(rᵢ).
Each +q is l from A: together they give 2×(kq)/l.
Each -q is across the square: r=√(2l)²+l²=√5 l, so together they give -2×(kq)/(√5 l).
V_A=(2kq)/l-(2kq)/(√5 l)=(2kq)/l[1-1/(√5)].
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