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Asked in GUJCET 2025 · Electrostatics of conductors
Given: a charge Q = 1.6×10⁻⁷ C spread uniformly over a conducting sphere of radius R.
Idea: all the charge sits on the outer surface, and inside a conductor the field is zero, so the potential inside is constant and equal to its value at the surface.
Potential inside: V = Q/(4πε₀ R).
Field at the surface: E = Q/(4πε₀ R²).
Dividing: V/E = Q/(4πε₀ R)×(4πε₀ R²)/Q = R.
The factor Q/(4πε₀) is common to both, so the value of the charge never enters the answer.
So the ratio is R, and it has the unit of length, as a potential divided by a field must.
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