A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80 μC m⁻². The charge on the sphere is

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(1) 1.45 mC. Given: diameter 2.4 m, so the radius is r=1.2 m; σ=80 μC m⁻²=80×10⁻⁶ C m⁻². Idea: the charge is spread over the outer surface, so Q=σ×4π r². Area: 4π r²=4×3.14×(1.2)²=18.1 m² Q=80×10⁻⁶×18.1=1.45×10⁻³ C=1.45 mC Take care to halve the diameter first: using 2.4 m as the radius would make the area, and the charge, four times too big.

A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80 μC m⁻². The charge on the sphere is

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