Practice portal › Electric Charge and Properties › Field of Spheres, Shells and Cylinders
Asked in GSEB Board July 2023 · Shell and uniform solid sphere
Idea: apply Gauss's law on a concentric sphere of radius r larger than the shell's radius R.
By symmetry ⃗E is radial and has the same size all over this sphere, so the flux is E×4π r².
The sphere encloses the whole charge Q: E×4π r²=Q/(ε₀)
E=1/(4πε₀)Q/(r²) - exactly the field of a point charge Q placed at the centre.
Inside the shell the same argument encloses no charge, so there E=0.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer