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Asked in GUJCET 2017 · Torque, energy and work done
Given: dipole moment P, initially along ⃗E (θ₁ = 0°), turned to θ₂ = 180°.
Idea: the work done in rotating a dipole equals the rise in its potential energy U = -PE cos θ: W = PE(cos θ₁ - cos θ₂).
W = PE(cos 0° - cos 180°) = PE (1 - (-1))
W = 2PE
The dipole moves from its most stable position (U = -PE) to its least stable one (U = +PE).
So the work done is 2PE.
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