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A molecule of a substance has a permanent electric dipole moment of magnitude 10⁻²⁹ C m. Two moles of this substance are polarised (at low temperature) by applying a strong electrostatic field of magnitude 10⁶ V m⁻¹. What is the potential energy of the dipoles in this field? [1 mole of the substance contains 6×10²³ molecules]

Asked in GUJCET 2022 · Torque, energy and work done

Answer: (2) -12 J

Step-by-step solution

Given: p=10⁻²⁹ C m per molecule; E=10⁶ V m⁻¹; 2 moles, so N=2×6×10²³=1.2×10²⁴ molecules.

Idea: a strong field at low temperature polarises the sample completely - every dipole lines up with the field, θ=0°.

One aligned dipole: U₁=-pE cos 0°=-10⁻²⁹×10⁶=-10⁻²³ J

All of them: U=NU₁=1.2×10²⁴×(-10⁻²³)=-12 J

The negative sign means energy would have to be supplied to pull the dipoles out of alignment.

Why the other options are wrong

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