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What is the de-Broglie wavelength of a bullet of mass 0.033 kg travelling at the speed of 1 km/s? (h = 6.6 × 10⁻³⁴ Js)

Asked in GUJCET 2025 · de Broglie relation and its graphs

Answer: (2) 2 × 10⁻³⁵ m

Step-by-step solution

Given: m = 0.033 kg, v = 1 km/s = 1000 m s⁻¹, h = 6.6×10⁻³⁴ J s.

Idea: de Broglie's relation λ = h/p, with p = mv for the bullet.

mv = 0.033×1000 = 33 kg m s⁻¹

λ = (6.6×10⁻³⁴)/(33) = 2×10⁻³⁵ m

The division is exact: 6.6÷33 = 0.2, so λ = 0.2×10⁻³⁴ m with no rounding.

So the bullet's de-Broglie wavelength is 2×10⁻³⁵ m.

Why the other options are wrong

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