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The de Broglie wavelength of a particle moving with velocity 2.25×10⁸ m s⁻¹ is the same as the wavelength of a photon. The ratio of the kinetic energy of the particle to the energy of the photon is ______. (Velocity of light c = 3×10⁸ m s⁻¹)

Asked in RS Academy GUJCET booklet · Matter wave against photon

Answer: (2) 3/8

Step-by-step solution

Given: v = 2.25×10⁸ m s⁻¹, c = 3×10⁸ m s⁻¹, equal wavelengths.

Idea: λ = h/p for both, so equal wavelengths mean equal momenta p.

Particle: K = 1/2mv² = 1/2pv (the course treats the particle non-relativistically, as the options assume).

Photon: E = pc.

K/E = (1/2pv)/(pc) = v/(2c)

K/E = (2.25×10⁸)/(2×3×10⁸) = 0.375

So the ratio is 3/8.

Why the other options are wrong

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