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Asked in GUJCET 2007 · de Broglie relation and its graphs
Idea: de Broglie's relation λ = h/p = h/(mv).
The wavelength depends on momentum, and so on mass and velocity.
Charge does not appear in the relation: a neutron and a proton with the same momentum have the same wavelength.
Charge matters only indirectly, for example through the energy qV a particle gains in an accelerating field.
So the wavelength of matter waves is independent of charge.
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