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Asked in GSEB Board March 2022 · Reactance and frequency
Idea: an inductor develops a back emf L(dI)/(dt), so it opposes the current more strongly the faster the current changes.
For I = I₀ sin ω t: V_L = L(dI)/(dt) = ω LI₀ cos ω t, so the voltage amplitude is V₀ = (ω L)I₀.
The ratio (V₀)/(I₀) is the reactance: X_L = ω L = 2π fL, measured in ohm.
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