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Asked in GSEB Board July 2022 · Behaviour of R, L and C separately
Given: V=V₀ sin ω t applied across a capacitor C.
Idea: the charge follows the voltage, q=CV=CV₀ sin ω t, and the current is its rate of change.
I=(dq)/(dt)=ω CV₀ cos ω t=I₀ sin (ω t+π/2).
The current reaches its peak a quarter cycle before the voltage does.
So the current leads the voltage by π/2.
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