Practice portal › Alternating Current › Power in AC Circuits
Asked in GUJCET 2013 · Average power and heating
Given: V₀=100 V, I₀=1.1 A, R=80 Ω and X_C=60 Ω.
Impedance: Z=√R²+X_C²=√80²+60²=100 Ω.
Power factor: cos φ=R/Z=(80)/(100)=0.8.
Average power: P=VᵣₘₛIᵣₘₛ cos φ=(V₀I₀)/2 cos φ=(100×1.1)/2×0.8=44 W.
(The data are not fully consistent: (V₀)/Z gives 1.0 A, not 1.1 A. The question intends P=VᵣₘₛIᵣₘₛ cos φ with the values given.)
So the power consumed is 44.0 W.
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