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Asked in CBSE AIPMT 1994 · Speed with temperature and molar mass
Given: T₁=27°C =300 K and T₂=927°C =1200 K.
Idea: vᵣₘₛ=√(3RT)/M, so vᵣₘₛ∝√T for a given gas.
Ratio of absolute temperatures: (T₂)/(T₁)=(1200)/(300)=4.
(v₂)/(v₁)=√4=2.
The rms speed is doubled.
Quadrupling the absolute temperature doubles the speed, because the speed goes as the square root.
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