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The molecules of a given mass of a gas have rms velocity of 200 m s⁻¹ at 27°C and 1.0×10⁵ N m⁻² pressure. When the temperature and pressure of the gas are respectively 127°C and 0.05×10⁵ N m⁻², the rms velocity of its molecules in m s⁻¹ is

Asked in NEET 2016 Phase-I · Speed with temperature and molar mass

Answer: (4) (400)/(√3)

Step-by-step solution

Given: v₁=200 m s⁻¹ at T₁=27°C=300 K; wanted at T₂=127°C=400 K.

Idea: vᵣₘₛ=√(3RT)/M depends on the temperature alone for a fixed gas — the pressure drops out.

(v₂)/(v₁)=√(T₂)/(T₁)=√(400)/(300)=2/(√3).

v₂=200×2/(√3).

v₂=(400)/(√3) m s⁻¹.

Why the other options are wrong

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