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Asked in NEET 2016 Phase-I · Speed with temperature and molar mass
Given: v₁=200 m s⁻¹ at T₁=27°C=300 K; wanted at T₂=127°C=400 K.
Idea: vᵣₘₛ=√(3RT)/M depends on the temperature alone for a fixed gas — the pressure drops out.
(v₂)/(v₁)=√(T₂)/(T₁)=√(400)/(300)=2/(√3).
v₂=200×2/(√3).
v₂=(400)/(√3) m s⁻¹.
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