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Asked in NEET 2023 · Speed with temperature and molar mass
Given: T₁=-50°C=223 K; the rms speed is increased by 3 times, so the final speed is v+3v=4v.
Idea: vᵣₘₛ=√(3RT)/M, so vᵣₘₛ∝√T for a fixed gas.
(v₁)/(v₂)=√(T₁)/(T₂), and here v/(4v)=1/4.
1/(16)=(223)/(T₂).
T₂=16×223=3568 K.
T₂=3568-273=3295°C.
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