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A point charge Q is placed inside a cavity within a solid isolated conducting sphere. Consider points A, B and C as shown in the figure, where the magnitudes of the electric fields are E_A, E_B and E_C, respectively. The points B and C are at the same distance from the center of the solid sphere. The correct option is :

Asked in Re-NEET 2026 · Conductors and electrostatic shielding

Figure: Conductors and electrostatic shielding
Answer: (2) E_A eq0, E_B=E_C

Step-by-step solution

A lies in the cavity, close to Q: the field of Q (and of the charge induced on the cavity wall) is not zero there, so E_A eq0.

The metal shields the outside from the cavity: charge -Q collects on the cavity wall and +Q spreads uniformly over the outer surface.

Outside, the field is that of +Q at the centre: E=(kQ)/(r²), the same at B and C, which are equally far from the centre.

So E_A eq0 and E_B=E_C.

Why the other options are wrong

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