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Asked in Re-NEET 2024 · Conductors and electrostatic shielding
On a conductor the charge resides on the outer surface. Area =6a²=6×(5×10⁻²)²=1.5×10⁻² m².
σ=Q/A=(6×10⁻⁶)/(1.5×10⁻²)=4×10⁻⁴=0.4×10⁻³ C m⁻².
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