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Asked in NEET 2024 · Potential due to a dipole
The potential of a short dipole at distance r and angle θ from its axis is V=(kP cos θ)/(r²), with k=1/(4πε₀).
On the axis θ=0° or 180°, so V=±(kP)/(r²).
V=±(9×10⁹×4×10⁻⁶)/(2²)=±9×10³ V, so A is true.
R carries a factor of 2 that belongs to the axial field E=(2kP)/(r³). It would give ±1.8×10⁴ V, so R is false.
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