Practice portal › Current Electricity › Kirchhoff's Laws and Circuit Analysis
Asked in NEET 2023 · Kirchhoff's laws in networks
The two cells oppose each other (their like terminals face each other at E), so the net emf is 10-5=5 V, in the direction the 10 V cell drives.
Total resistance round the loop: 2+1+7=10 Ω.
I=5/(10)=0.5 A.
The 10 V cell pushes current out of its long (positive) plate, towards E and on to B: the current is from A to B through E.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer