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The sliding contact C is at one fourth of the length of the potentiometer wire (AB) from A as shown in the circuit diagram. If the resistance of the wire AB is R₀, then the potential drop (V) across the resistor R is

Asked in Re-NEET 2022 · Kirchhoff's laws in networks

Figure: Kirchhoff's laws in networks
Answer: (2) (4V₀R)/(3R₀+16R)

Step-by-step solution

R is connected across AC, which has resistance (R₀)/4; CB has (3R₀)/4 and is in series with that pair.

R_∥=((R₀/4)R)/(R₀/4+R)=(R₀R)/(R₀+4R).

Divider: V=V₀(R_∥)/(R_∥+3R₀/4)=V₀(R₀R)/(R₀R+3/4R₀(R₀+4R)).

V=V₀(4R)/(4R+3R₀+12R)=(4V₀R)/(3R₀+16R).

Why the other options are wrong

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