Practice portal › Thermodynamics › Work Done in a Thermodynamic Process
Asked in JEE Main 2016 · Work from a Stated P-V Law
The process A to B is the straight line in the figure, running from
A(V₀,2P₀) down to B(2V₀,P₀), so P=3P₀-(P₀)/(V₀)V.
T=(PV)/(nR)=1/(nR)(3P₀V-(P₀)/(V₀)V²).
(dT)/(dV)=0 gives 3P₀=(2P₀)/(V₀)V, so V=3/2V₀.
Tₘₐₓ=1/(nR)((9P₀V₀)/2-(9P₀V₀)/4)=(9P₀V₀)/(4nR).
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