Practice portal › Thermodynamics › Work Done in a Thermodynamic Process
Asked in JEE Main 25th Feb 1st Shift 2021 · Work from a Stated P-V Law
P=kV³, so W=∫_V₁^V₂kV³dV=k/4(V₂⁴-V₁⁴)=(P₂V₂-P₁V₁)/4.
For an ideal gas PV=nRT, so W=(nR(T₂-T₁))/4.
T₂-T₁=200 K, so W=(200nR)/4=50 nR.
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