A body of mass 500 g moves along the x-axis such that its velocity varies with displacement x according to the relation v=10√x m/s. The force acting on the body is

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(4) 25 N. Idea: the speed is given against position, so the acceleration is a=v(dv)/(dx). v=10√x, so (dv)/(dx)=(10)/(2√x)=5/(√x). a=v(dv)/(dx)=10√x×5/(√x)=50 m/s², a constant. F=ma=0.5×50=25 N. The √x cancelling is the point: a speed going as √x is exactly uniform acceleration.

A body of mass 500 g moves along the x-axis such that its velocity varies with displacement x according to the relation v=10√x m/s. The force acting on the body is

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