Three forces F₁=10 N, F₂=8 N, F₃=6 N are acting on a particle of mass 5 kg. The forces F₂ and F₃ are applied perpendicularly so that the particle remains at rest. If the force F₁ is removed, then the acceleration of the particle is

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(2) 2 m s⁻². Idea: if the particle is at rest under three forces, F₁ must be exactly balancing the resultant of the other two. Remove it and that resultant is what is left. F₂ and F₃ are perpendicular, so their resultant is √8²+6²=√64+36=√100=10 N. That matches F₁=10 N, which confirms the particle really was in equilibrium. With F₁ gone the net force is 10 N. a=(10)/5=2 m s⁻², directed opposite to where F₁ pointed.

Three forces F₁=10 N, F₂=8 N, F₃=6 N are acting on a particle of mass 5 kg. The forces F₂ and F₃ are applied perpendicularly so that the particle remains at rest. If the force F₁ is removed, then the acceleration of the particle is

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