Calculate the amount of charge on capacitor of 4 μF. The internal resistance of battery is 1 Ω. [Figure: three parallel branches between a left vertical wire and a right vertical wire. Top branch: a 4 μF capacitor, a 6 Ω resistor, and a parallel pair of two 2 μF capacitors, all in series. Middle br…

Question

Calculate the amount of charge on capacitor of 4 μF. The internal resistance of battery is 1 Ω. [Figure: three parallel branches between a left vertical wire and a right vertical wire. Top branch: a 4 μF capacitor, a 6 Ω resistor, and a parallel pair of two 2 μF capacitors, all in series. Middle branch: a 5 V battery. Bottom branch: a 4 Ω resistor.]

Accepted Answer

(2) 8 μC. In steady state the capacitor branch carries no current. Battery current through 4 Ω: I=5/(4+1)=1 A; terminal voltage =4 V. Capacitor branch: 4 μF in series with (2+2)=4 μF, equivalent 2 μF. The 6 Ω has no drop, so the branch has 4 V. Q=2×4=8 μC, the charge on the 4 μF capacitor.

Step-by-step solution

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