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Two resistors 400 Ω and 800 Ω are connected in series across a 6 V battery. The potential difference measured by a voltmeter of 10 kΩ across 400 Ω resistor is close to

Asked in JEE Main 3rd Sept 2nd Shift 2020 · Ammeters and voltmeters in circuits

Answer: (4) 1.95 V

Step-by-step solution

The voltmeter is in parallel with 400 Ω: Rₚ=(400×10000)/(10400)=384.6 Ω.

Total resistance =384.6+800=1184.6 Ω.

Reading =6×(384.6)/(1184.6)=1.95 V.

Why the other options are wrong

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