The distance between two slits is 3 mm and the screen is placed 2 m away. When blue-green light of wavelength 500 nm is used, the distance between two consecutive fringes is .

Question

Accepted Answer

(3) 0.33 mm. Given: d = 3 mm = 3×10⁻³ m, D = 2 m, λ = 500 nm = 5×10⁻⁷ m. Idea: consecutive fringes are one fringe width apart, and the fringe width of a two-slit pattern is β = (λ D)/d. β = ((5×10⁻⁷)(2))/(3×10⁻³) = (1×10⁻⁶)/(3×10⁻³). β = 3.33×10⁻⁴ m. The fringes are 0.33 mm apart.

The distance between two slits is 3 mm and the screen is placed 2 m away. When blue-green light of wavelength 500 nm is used, the distance between two consecutive fringes is ________.

Step-by-step solution

Why the other options are wrong