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Asked in GUJCET 2022 · Fringe width and fringe position
Given: d=3 mm=3×10⁻³ m, D=2 m, λ=600 nm=6×10⁻⁷ m.
Idea: consecutive bright fringes in Young's experiment are separated by the fringe width β=(λ D)/d.
β=(6×10⁻⁷×2)/(3×10⁻³).
(6×2)/3=4 and (10⁻⁷)/(10⁻³)=10⁻⁴.
β=4×10⁻⁴ m=0.4 mm.
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