Light of wavelength 500 nm is used in a Young's double slit experiment. The distance between the slits and the screen is 100 cm and the slits are separated by 1 mm. Find the distance between the fifth and the third bright fringes.

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(1) 1 mm. Given: λ=500 nm=5×10⁻⁷ m, D=100 cm=1 m, d=1 mm=10⁻³ m. Idea: bright fringes are evenly spaced by β=(λ D)/d, so the gap between the n-th and the m-th of them is (n-m)β. β=(5×10⁻⁷×1)/(10⁻³)=5×10⁻⁴ m=0.5 mm. The fifth and third bright fringes are 5-3=2 fringe widths apart. y₅-y₃=2×0.5 mm. =1 mm.

Light of wavelength 500 nm is used in a Young's double slit experiment. The distance between the slits and the screen is 100 cm and the slits are separated by 1 mm. Find the distance between the fifth and the third bright fringes.

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