For blind students only : If the refractive index of a prism with small prism angle is 1.6 and angle of minimum deviation is 2.4. Then prism angle of prism is .

Question

Accepted Answer

(1) 4°. Given: a prism of small refracting angle, n=1.6, and a minimum deviation of 2.4° (the paper prints 2.4 with no degree sign, but every option is in degrees). Idea: for a thin prism the deviation is δ=(n-1)A and does not depend on the angle of incidence, so no minimum-deviation geometry is needed. Rearranging, A=δ/(n-1)=(2.4°)/(1.6-1). The denominator is 0.6, so A=(2.4°)/(0.6). The prism angle is A=4° — small, as the question assumed.

For blind students only : If the refractive index of a prism with small prism angle is 1.6 and angle of minimum deviation is 2.4. Then prism angle of prism is ________.

Step-by-step solution

Why the other options are wrong