Practice portal › Electromagnetic Waves › Uses of the Bands, and lambda nu = c
Asked in GUJCET 2022 · Wavelength, frequency and photon energy
Given: u₁=6 MHz=6×10⁶ Hz and u₂=12 MHz=12×10⁶ Hz.
Idea: λ=c/u, so the highest frequency of the band gives its shortest wavelength.
λ₁=(3×10⁸)/(6×10⁶)=50 m.
λ₂=(3×10⁸)/(12×10⁶)=25 m.
So the set tunes over the band 25 m to 50 m.
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