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Asked in RS Academy GUJCET booklet · Capacitance of a conductor and a capacitor
Given: plate radius r=2.0 cm=0.02 m; sphere radius R=100 cm=1 m.
Idea: set the two capacitances equal and solve for the gap d.
Parallel plates: C=(ε₀π r²)/d. Isolated sphere: C=4πε₀R.
(ε₀π r²)/d=4πε₀R gives d=(r²)/(4R).
d=((0.02)²)/(4×1)=(4×10⁻⁴)/4=1×10⁻⁴ m, a tenth of a millimetre.
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