Practice portal › Electric Potential and Capacitance › Electric Potential
Asked in RS Academy GUJCET booklet · Relation between field and potential
Given: uniform field ⃗E = E ̂j with E > 0; A (0, 0), B (2, 0), C (0, 2).
Idea: the potential falls along the field: V(y) = V₀ - Ey, and it does not depend on x.
A and B both have y = 0, so they lie on the same equipotential plane: V_A = V_B.
C is at y = 2, further along the field: V_C = V_A - 2E, so V_A > V_C.
So V_A = V_B and V_A > V_C.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer