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Asked in GUJCET 2023 · Equipotential surfaces and V-r graphs
Given: charge Q at the centre; q is moved between two points on the circle of radius r = 10 cm.
Idea: the work done depends only on the potential difference between the end points: W = q(V₂ - V₁).
Every point on the circle is the same distance r from Q, so V₁ = V₂ = (KQ)/r: the circle lies on an equipotential surface.
W = q×0 = 0.
So the work done is 0 J, whatever path is taken between the two points.
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