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How will you connect four capacitors, each of capacitance 4 μF, to obtain an equivalent capacitance of 1.6 μF?

Asked in GUJCET 2022 · Series and parallel combinations

Answer: (1) Two in parallel and two in series

Step-by-step solution

Given: four capacitors of 4 μF; target 1.6 μF.

Idea: the target is less than one capacitor, so some series connection is needed; test the groupings.

Two in parallel: 4 + 4 = 8 μF.

Put this in series with the other two (each in series): 1/C = 1/8 + 1/4 + 1/4 = 5/8.

C = 8/5 = 1.6 μF.

So: two in parallel, with that pair in series with the other two.

Why the other options are wrong

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