Charges of 1 μC are placed at each of the four corners of a square of side 2√2 m. The potential at the point of intersection of the diagonals is . (K=9×10⁹ SI unit)

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(1) 18×10³ V. Given: four charges q=1 μC at the corners of a square of side a=2√2 m. Idea: potential is a scalar, so the four contributions simply add — no directions to worry about. Diagonal: a√2=2√2×√2=4 m, so each corner is r=2 m from the centre. One charge: (Kq)/r=(9×10⁹×10⁻⁶)/2=4.5×10³ V. All four: V=4×4.5×10³=18×10³ V. (The field at the centre is zero by symmetry, but the potential is not.)

Charges of 1 μC are placed at each of the four corners of a square of side 2√2 m. The potential at the point of intersection of the diagonals is ______. (K=9×10⁹ SI unit)

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