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Asked in GUJCET 2017 · Relation between field and potential
Idea: in a uniform field the potential falls steadily in the direction of ⃗E and is constant on every plane perpendicular to it.
The field is along +X, so V depends only on x: V(x)=V₀-Ex.
P is at x=0 and Q at x=2, further along the field, so V_P>V_Q (by 2E).
R is at x=0, on the same perpendicular line as P, so V_P=V_R.
Therefore V_P>V_Q and V_P=V_R.
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