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Asked in GSEB Board March 2023 · Induced current, heat and power
Given: Φ(t) = 2t² + 2t + 1 (in Wb), R = 10 Ω, t = 2 s.
Idea: the induced emf is |ε| = |(dΦ)/(dt)|, and the current is I = (|ε|)/R.
(dΦ)/(dt) = 4t + 2.
At t = 2 s: |ε| = 4(2) + 2 = 10 V.
I = (10)/(10) = 1 A.
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