Practice portal › Electromagnetic Induction › Faraday's Law
Asked in GSEB Board July 2016 · Induced charge
Given: A = 100 cm² = 100×10⁻⁴ = 0.01 m², N = 50, B = 0.02 T, R = 2 Ω.
Idea: the charge that flows depends only on the total change of flux linkage, Q = (N |ΔΦ|)/R, not on how quickly it happens.
Flux per turn at the start: BA = 0.02×0.01 = 2×10⁻⁴ Wb; after removal it is 0.
Change of flux linkage: N|ΔΦ| = 50×2×10⁻⁴ = 0.01 Wb.
Q = (0.01)/2 = 0.005 C (the 1 s does not enter).
So the induced charge is 0.005 C.
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