Practice portal › Electromagnetic Induction › Magnetic Flux
Asked in GSEB Board August 2020 · Flux through a surface
Given: the square lies in the xy plane, so its area vector is ⃗A = L²̂k; ⃗B = B₀(2̂i + 3̂j + 4̂k).
Idea: flux counts only the component of ⃗B along the normal to the surface, Φ = ⃗B·⃗A.
Φ = B₀(2̂i + 3̂j + 4̂k)· L²̂k.
Since ̂i·̂k = ̂j·̂k = 0 and ̂k·̂k = 1: Φ = 4B₀L².
Magnitude of the flux = 4B₀L² Wb.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer