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Asked in GSEB Board July 2017 · Induced current, heat and power
Given: Φ = 6t² - 5t + 1 (in Wb), R = 10 Ω, t = 0.5 s.
Idea: the induced emf is the rate of change of flux, |ε| = |(dΦ)/(dt)|; the current then follows from Ohm's law.
(dΦ)/(dt) = 12t - 5.
At t = 0.5 s: (dΦ)/(dt) = 12(0.5) - 5 = 1 V.
I = (|ε|)/R = 1/(10) = 0.1 A.
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