A coil has N turns and current passes through it is I ampere then we obtain L Henry of self inductance. Now if current charge to 5I then new self inductance will be H.

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(4) L. Idea: self-inductance is defined by Φ = LI, where Φ is the total flux linked with the coil. For a coil with a fixed (air) core, Φ is proportional to I, so L = Φ/I is a constant of the coil. It depends only on how the coil is built - number of turns, size and core: for a solenoid L = (μ₀N²A)/ℓ. Raising the current to 5I multiplies the flux by 5 as well, leaving the ratio unchanged. So the new self-inductance is still L henry. (The paper prints 'current charge to 5I'; it means the current is changed to 5I.)

A coil has N turns and current passes through it is I ampere then we obtain L Henry of self inductance. Now if current charge to 5I then new self inductance will be _________ H.

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